X – y = 6xy asked in Linear Equations by Anika01 (571k points) pair of linear equations in two variables; 1 Answer Dhruv G 2x y = 5 3x y = 10 By solving this equation by eliminating method y and y would get canceled, leaving 2x 3x = 5 10 5x = 15 x = 3Solve the given pair of linear equations by elimination method 2xy5=0 and 3x2y4=0 Solve by matrix method 2x3y = 5, 3xy = 2 Solve the following simultaneous equations using elimination method 3x 4y 5 = 0 , y = x 4
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5/x-3/y=1 3/2x+2/3y=5 by elimination method-1 Solve the system using substitution method 2x 3y = 5 x y = 5 2 Solve using elimination my addition method 4x 3y = 8 5x 6y = 1 3 Solve for (x,y,z) 3x 2yz = 2 4x y 2z = 11 3x 2y z = 6 4 Solve, list all ordered pairs separately 3x2 y2 = 18 2x2 3y2 = 10 5 Multiplying equation (i) x 3 and (ii) x 1 we get, 9u – 3v = 27 (iii) 2u 3v = 5 (iv) Adding equation (iii) and (iv) we get , 9u 2u – 3v 3v = 27 5 ⇒ 11u = 22 ⇒ u = 2 Now putting u = 2 in equation (iv) we get, 2(2) 3v = 5 ⇒ 3v = 9 ⇒ v = 3 Hence, x = 1/u = −1/2 and, y = 1/v = 1/3
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Given system of equations are xy= 5 (1) 2x3y=5 (2) multiply (1) by 3 we get 3x3y=15 (3) Now , add (2) and (3) , we get => 5x = Ex 34, 1 (Elimination) Solve the following pair of linear equations by the elimination method and the substitution method (i) x y = 5 and 2x – 3y = 4 x y = 5 2x – 3y = 4 Multiplying equation (1) by 2 2(x y) = 2 × 5 2x 2y = 10 Solving (3) and (2) by Elimination –5y = –6 5y = 6 y = 𝟔/𝟓 Putting y = 6/5 in (1) x y = 5 x 6/5 = 5 x = 5 – 6/5 x = (5 × 5 − 6)/5 x = (25 − 6)/5 x = 𝟏𝟗/𝟓 Hence, x(a) 2x 3y = 12(i) and x y = 1(ii) (ii)×3 ==> 3x 3y = 3(iii) Now we can eliminate y by adding (i) & (iii) (i) (iii) ==> 5x = 15 so x=3
X Y 5 And 2x 3y 4 By Elimination Method Scholr X y=5 2x3y=5 X y=5 2x3y=5Question 1 Solve the following pair of linear equations by the elimination method and the substitution method (i) xy=5 and 2x 3y = 4 (i) 3x 4y = 10 and 2x 2y = 2 (iii) 3x 5y 4 0 and 9x = 2y 7Begin with 2x 3y = 5 Subtract 2x from each side3y = 5 2x Divide both sides by 3 y = 5/3 2x/3 Solve the following system of equations by elimination method x y = 2xy; x = 1 y = 2 Ok So prefer the elimination method, but you can do this with substitution as well First put the equations on top of each other x 2y= 5 2x3y=4 Then find the variable that would be easiest to cancel out I think it's x because you only have to modify one of the equations Let's multiply the first equation by 2 This will allow us to cancel out the two x's in the equations
⇒ x = 3 ∴ Solution is x = 3 and y = 2 Concept Methods of Solving Simultaneous Linear Equations by Elimination Method Method of Elimination by Equating CoefficientsSolve the following pair of linear equations by elimination method xy=5 and 2x3y=4 Solve the following pair of linear equations by the elimination method and the substitution method Using elimination method, If 2x 3y = 12 and 3x 2y = 5 thenClick here👆to get an answer to your question ️ Solve the equation by substitution method 2x 3y = 9 , 3x 4y = 5 Join / Login > 10th > Maths > Pair of Linear Equations in Two Variables > Algebraic Methods of Solving a Pair of Linear Equations > Solve the equation by subst maths Solve the equation by substitution method 2 x 3 y = 9, 3 x 4 y = 5 Easy Answer We have, 2 x 3 y
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Multiply the both sides of the first equation by 2 Distribute and multiply Now add the equations together You can do this by simply adding the two left sides and the two right sides separately like this Group like termsXy=0 2x3y=5 solve suing elimination method See answers (2) Ask for details ;Graphical method Find the x and y intercept of each line, draw the lines on the same set of cartesian coordinates, and look at where the lines cross (x, y) = (1, 1) Abdullahi Aminu Muhammad , former Student Answered 1 year ago Author has 115 answers and 262K answer views 2x3y=5 (×3) 3xy=4 (×2) 6x9y=15A
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x y = 5 >1 2x 3y = 4 >2 by elimination, 2x 2y = 10 2x 3y =4 _____5y = 6 y = 6/5 >3 putting eq no 3 into 1, we get , x y = 5 x 6/5 = 5 after solving , 5x 6 = 25 5x = 19 x = 19/5 >4 x = 19/4 y = 6/5 hope it will help youXy = 5 −(1)2x−3y =4 −(2)Multiplying eqn (1) with 3 and adding to eqn (2)−3x3y = 15 2x−3y = 4__________________5x0y =19∴ x= 519 = 38Substituting in eqn (1)−y = 5−x = 5−38 = 12∴ xPutting x = 0, we get y = 5 Putting x = 2, we get y = 1 Thus, we have the following table for the equation 3x – y = 5 x1 02 y 2 51 Now, plot the points P (0, 5) and Q (2, 1) The point A (1, 2) has already been plotted Join PA and QA and extend it on both ways Thus, PQ is the graph of 3x y = 5 The two graph lines intersect at A (1 2) ∴x = 1 and y = 2 are the
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Answers 1 Get Other questions on the subject Mathematics Mathematics, 1349, cpalabamagirl2595 23) 84% of a contractor's jobs involves electrical work 75% of a contractor's jobs involve plumbing work Of the jobs that involve plumbing, 90% of the jobs also involves electrical work Let E = jobs involvingWelcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries Students (upto class 102) So the solution is {x = 3 y = 7 By adding both equations In the initial system the coefficients of y are opposite numbers −1 and 1, so if we add both equations we get an equation with x variable only 5x = 15 x = 3 Now we can calculate the remaining variable y by substitution 3 y = 10 ⇒ y = 7 Graphically
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Solve by using elimination methodxy=5,2x3y=5 Get the answers you need, now!Steps for Solving Linear Equation 2x3y = 5 2 x 3 y = 5 Subtract 2x from both sides Subtract 2 x from both sides 3y=52x 3 y = 5 − 2 x Divide both sides by 3 Divide both sides by 3What is x3y=3 and 2x3y=5 using elimination method?
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Xy=0 2x3y=5 solve using elimination method Get the answers you need, now! Solve for x and y 3/x 1/y 9 = 0 , 2/x 3/y = 5 asked Jun 22 in Linear Equations by Gavya (334k points) linear equations in two variables;\\begin{aligned}&x2y=10\\&2xy=5\end{aligned}\ > <
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Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries Students (upto class 102) preparing for All Government Exams, CBSE Board Exam,Chetanreddy584 chetanreddy584 Math Secondary School answered Solve by using elimination methodxy=5,2x3y=5 2 See answers1 Solve the system by any method 2x5y=1 2xy=1 How many solutions does the system of equations below have?
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X3y=5 2x3y=1 substitution method X3y=5 2x3y=1 substitution method Solve the following pair of linear equations by the elimination method and the substitution method Solve each pair of equation by using the substitution method 2x3y=9 and 3x4y=5 Solve the following system of equations by using the method of substitution 2x3y=9,quad 3x4y=5 Solve (by any method) xAlgebra 2 If you were to use the substitution method toXy=0 2x3y=5 solve using elimination method Other questions on the subject Mathematics Mathematics, 1600, Alexishp33 What is the length of the unknown leg in
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Solve using the elimination method 2x3y=5 2xy=1 xy=6 xy=4 30,777 results, page 8 Math Use the matrix method to solve 5x3y=35 3x4y=8 Math Solve by elimination 5x7y=77 , 5x3y=53 can you please help me out step by step so I can understand it on my own, thanks Maths solve in simultaneous method a2b=13 2a3b=5 Algebra To solve the following system of equations by eliminationI don't understand how to do this, sorry ;;Correct answer Solve by elimination methodxy=5, 2x3y=5 eanswersincom
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Solve using the elimination method 2x3y=5 2xy=1 xy=6 xy=4 30,918 results, page Working in pairs and exchanging practice questions c) Developing a personal method that is right for you and Calculus II Finding the volume of a revolutionVisit http//ilectureonlinecom for more math and science lectures!In this lecture series I'll show you how to solve for multiple variables simultaneously usX y =5 and 2x –3y = 4 By elimination method x y =5 (i) 2x –3y = 4 (ii) Multiplying equation (i) by (ii), we get 2x 2y = 10 (iii) 2x –3y = 4 (ii) Subtracting equation (ii) from equation (iii), we get 5y = 6 y = 6/5 Putting the value in equation (i), we get x = 5 (6/5) = 19/5 Hence, x = 19/5 and y = 6/5 By substitution method
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Elimination Method xy = 5 and 2x3y = 4LinkedIn Profilehttps//wwwlinkedincom/in/arunmamidi8ba/FaceBookhttps//wwwfacebookcom/arunkumarm1447Solve for x and y, using substitution method 2x y = 7, 4x 3y 1 =0 Solve each pair of equation by using the substitution method x2y=1 and 2x3y=12 Solve the following pair of linear equations by the elimination method and the substitution methodExplain your answer y=3/5x1 y=6/10x3 plz help me ;;
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